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Photo electric current depends on the intensity of incident lightWork function of caesium and platinum are 2.14eV and 5.65eV respectively. Which one of the metal has higher threshold wavelength? Why? |
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Answer» Solution :Threshold frequency of CAESIUM `V_0=(omega_0/h) =((2.14xx1.6xx10^-19 )/(6.6xx10^-34))=0.52xx10^15` HZ Threshold wavelength of caesium `lambda_0=C/V_0)=((3xx10^8)` /(0.52xx10^15))=5.77xx10^-7m` |
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