1.

Photo electric current depends on the intensity of incident lightWork function of caesium and platinum are 2.14eV and 5.65eV respectively. Which one of the metal has higher threshold wavelength? Why?

Answer»

Solution :Threshold frequency of CAESIUM `V_0=(omega_0/h) =((2.14xx1.6xx10^-19 )/(6.6xx10^-34))=0.52xx10^15` HZ
Threshold wavelength of caesium `lambda_0=C/V_0)=((3xx10^8)` /(0.52xx10^15))=5.77xx10^-7m`


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