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Photo electrons are emitted with a maximum speed of 7xx10^(5)ms^(-1) from a surface when light of frequency 8xx10^(14)Hz is incident on it, the threshold frequency for this surface is : |
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Answer» `2.32xx10^(14)Hz` `=8XX10^(14)-(9.1xx10^(-31)xx49xx10^(10))/(2xx6.63xx10^(-34))` `=8xx10^(14)3.63xx10^(14)=4.64xx10^(14)Hz` |
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