1.

Photocell is kept at distance of 1 m from the source and incident radiation .Now distance from source is changed to 2m,then….

Answer»

no. of PHOTOELECTRON emitted are `(1)/(4)` times intital value.
energy of electron emitted is `(1)/(4)` times intitial energy
no. of electron emitted is HALF of intital electron emitted.
Energy of electron emitted is half of initial energy

Solution :POWER `PROP` NUMBER of electron emitted N.
Power `prop(1)/(2)impliesNprop (1)/(r^(2))`


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