1.

Photon of 5.5 eV energy falls on the surface of the metal emitting photoelectrons of maximum kinetic energy 4.0 eV. The stopping voltage required for these electrons are

Answer»

5.5 V
1.5V
9.5V
4.0V

Solution :As `K_(max)=4.0eV` hence stopping POTENTIAL `V_(0)=(K_(max))/(e)=4.0V`


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