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Photons absorbed in matter are converted to heat.A source emitting n photon /sec of frequency v is used to convert 1 kg of ice at 0 ""^(@)C to water at 0""^(@)C.Then the time T taken for the conversion |
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Answer» decreases with increasing n,with v fixed. `P=(E_(n))/(t)=(n.hv)/(t)=((n.)/(t))hv` `therefore` P=nhv (`because` Here `(n.)/(t)`=no. of photons) emitted per unit time =n(given) Energy obtained by given amount of ICE in time T,E.=PT `therefore` mL=(nhv)T(From equation (1)) L=latent HEAT of fusion of ice) `therefore T=(mL)/(nhv)` `therefore Tprop(1)/(nv)` (`BEACUSE` m,L,h are constant).....(2) From equation (2), (i)If v=constant then by increasing n,T will DECREASE. `implies` Option (A) is correct. (ii)If n =constant then by increasing v,T will decrease `implies`Option (B) is correct . (iii)If nv=constant then T=constant. `impliesOption (C) is correct. |
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