1.

Photons of energy 1 eV and 2.5 eV sucesseively illuminate a metal,whose work function is 0.5 eV,the ratio of maximum speed of emitted electron is…..

Answer»

`1:2`
`3:1`
`2:1`
`1:3`

SOLUTION :`((1)/(2)mv_(max)^(2))_(2)=(hf)_(2)-phi=2.5-0.5=2.0 eV`
`((1)/(2)mv_(max)^(2))_(2)=(hf)_(2)-phi=2.5-0.5=2.0eV`
`therefore ("Ratio")^(2)=(0.5)/(2)=(1)/(4)`
`therefore ((v_(max))_(1))/((v_(max))_(2))=(1)/(2)`


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