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Answer» `MnO_(2)` dissolves in conc.HCl but does not form `Mn^(4+)` ions (b)Decomposition of acidic `KMnO_(4)` is catalyst by sunlight `MnO_(4)^(-)+4H^(+) to 4MnO_(4)+2H_(2)O+3O_(2)` (c)`underset("green")(3K_(2)MnO_(4))+2H_(2)O to underset("purple")(2KMnO_(4)^(-)+underset("dark brown")(MnO_(2))(darr)+4KOH` (d) `KMnO_(4)` also acts as an OXIDIZING agent in alkaline medium. `MnO_(4)^(-)+2H_(2)O +3E^(-) to MnO_(2)+4OH^(-), E^(@)=+1.23` volt |
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