Pick out the expression for power in a rectangular conductor from the following.(a) P=\(\frac {B^2 l^2 v}{R}\)(b) P=\(\frac {B^2 lv^2}{R}\)(c) P=\(\frac {B^2 l^2 v^2}{R}\)(d) P=\(\frac {B^2 l^2 v^2}{R^2}\)I had been asked this question by my school principal while I was bunking the class.This intriguing question originated from Energy Consideration: A Quantitative Study topic in section Electromagnetic Induction of Physics – Class 12

Pick out the expression for power in a rectangular conductor from the

1.	Pick out the expression for power in a rectangular conductor from the following.(a) P=\(\frac {B^2 l^2 v}{R}\)(b) P=\(\frac {B^2 lv^2}{R}\)(c) P=\(\frac {B^2 l^2 v^2}{R}\)(d) P=\(\frac {B^2 l^2 v^2}{R^2}\)I had been asked this question by my school principal while I was bunking the class.This intriguing question originated from Energy Consideration: A Quantitative Study topic in section Electromagnetic Induction of Physics – Class 12
Answer» The CORRECT choice is (c) P=\(\frac {B^2 l^2 v^2}{R}\) Easy explanation: In a rectangular CONDUCTOR, the emf (E) is given ➔ Blv So, current (I) = \(\frac {E}{R} = \frac {Blv}{R}\) POWER (P) = I^2R P=\(\frac {B^2 l^2 v^2}{R}\) The work DONE is mechanical and this mechanical energy is dissipated as Joule heat.

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