1.

Pick out the incorrect statement w.r.t. NH_3

Answer»

It contains a lone pair of ELECTRONS, which can bonds to a proton to form tetrahedra `NH_(4)^(+)` ions
`N_2` is FORMED, when `NH,_3` is passed over heated copper (II) oxide
`NH_3` burns in air to form `N_2` and steam
In Ostwald process for the manufacture of `HNO_3, NH_3,` is oxidized in presence of Pt/Rh catalyst to give `NO and H_2O`

Solution :`NH_3`, SHOWS no reaction towards air. It burns with a pale green flame in oxygen.
`4NH_3+3O_(2) to 2N_(2)+6H_(2)`
a) NH, molecule is trigonal pyramidal is shape with a lone pair of electron in one of the four `sp^3` hybridized orbitals. When it is bonded to `H^+`, it forms tetrahedral `NH_(4^(+))` ions, because all the four sp hybrid orbitals possess four bonded pairs of electrons.
b). `2NH_(3)+3CuO to N_(2)+3H_(2)O+Cu`
d). `4NH_(3)+5O_(2) overset(Pt//Rh)to 4NO+6H_(2)O`


Discussion

No Comment Found