Pipe A Can Fill A Tank In 8 Hours And Pipe B Can Fill It In 6 Hours.

1.	Pipe A Can Fill A Tank In 8 Hours And Pipe B Can Fill It In 6 Hours. If Both The Pipes Are Opened But After 2 Hours Pipe A Is Closed, Then The Other Pipe Will Fill The Tank In ?
Answer» Tank part filled by Pipe A in 1 HOUR = 1/8 or Time taken to fill 1/8 part of tank filled A = 1 hour ------------- (1) Tank part filled by Pipe B in 1 HOURS = 1/6 or Time taken to fill 1/6 part of tank filled B = 1 hour ---------(2) => Tank Part filled by (A+B) in 1 hour = (1/8 + 1/6) => Tank Part filled by (A+B) in 2 hour = 2(1/8 + 1/6) = 2(3+4)/24 = 27/24 = 7/12 After 2 hours LEFT over portion of tank = (1-7/12) = 5/12 Time taken to fill 1/6 part of tank filled B = 1 hour so time taken to fill 5/12 part of tank by B = 6 5/12 = 5/2 = 2 1/2 => So it TAKES 2 1/2 hrs (2hrs 30 min) to fill 5/12 of tank. Tank part filled by Pipe A in 1 hour = 1/8 or Time taken to fill 1/8 part of tank filled A = 1 hour ------------- (1) Tank part filled by Pipe B in 1 hours = 1/6 or Time taken to fill 1/6 part of tank filled B = 1 hour ---------(2) => Tank Part filled by (A+B) in 1 hour = (1/8 + 1/6) => Tank Part filled by (A+B) in 2 hour = 2(1/8 + 1/6) = 2(3+4)/24 = 27/24 = 7/12 After 2 hours left over portion of tank = (1-7/12) = 5/12 Time taken to fill 1/6 part of tank filled B = 1 hour so time taken to fill 5/12 part of tank by B = 6 5/12 = 5/2 = 2 1/2 => So it takes 2 1/2 hrs (2hrs 30 min) to fill 5/12 of tank.

Pipe A Can Fill A Tank In 8 Hours And Pipe B Can Fill It In 6 Hours. If Both The Pipes Are Opened But After 2 Hours Pipe A Is Closed, Then The Other Pipe Will Fill The Tank In ?

Answer»

Tank part filled by Pipe A in 1 HOUR = 1/8

Time taken to fill 1/8 part of tank filled A = 1 hour ------------- (1)

Tank part filled by Pipe B in 1 HOURS = 1/6

Time taken to fill 1/6 part of tank filled B = 1 hour ---------(2)

=> Tank Part filled by (A+B) in 1 hour = (1/8 + 1/6)

=> Tank Part filled by (A+B) in 2 hour = 2*(1/8 + 1/6) = 2*(3+4)/24 = 2*7/24 = 7/12

After 2 hours LEFT over portion of tank = (1-7/12) = 5/12

Time taken to fill 1/6 part of tank filled B = 1 hour

so time taken to fill 5/12 part of tank by B = 6 * 5/12 = 5/2 = 2 1/2

=> So it TAKES 2 1/2 hrs (2hrs 30 min) to fill 5/12 of tank.

Tank part filled by Pipe A in 1 hour = 1/8

Time taken to fill 1/8 part of tank filled A = 1 hour ------------- (1)

Tank part filled by Pipe B in 1 hours = 1/6

Time taken to fill 1/6 part of tank filled B = 1 hour ---------(2)

=> Tank Part filled by (A+B) in 1 hour = (1/8 + 1/6)

=> Tank Part filled by (A+B) in 2 hour = 2*(1/8 + 1/6) = 2*(3+4)/24 = 2*7/24 = 7/12

After 2 hours left over portion of tank = (1-7/12) = 5/12

Time taken to fill 1/6 part of tank filled B = 1 hour

so time taken to fill 5/12 part of tank by B = 6 * 5/12 = 5/2 = 2 1/2

=> So it takes 2 1/2 hrs (2hrs 30 min) to fill 5/12 of tank.