1.

pK_a for acetic acid is 4.74. The concentration of CH_3COONa is 0.01 M. The pH of CH_3COONa is…….

Answer»

3.37
4.37
4.74
0.474

Solution :`[H^+]=C.a SQRT(K_a.C)`
`pH=-LOG(K_a.C)^(1/2)`
`=1/2[-log K_a-log c]`
`=1/2[4.74-log 10^-2]`
`=1/2[4.74+2]=3.37`
`pH=3.37`


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