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Plane wave of lamda=600 nm incident normally on a slit of width 0.18 mm. Calculate the total angular wideth of the central maximum. |
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Answer» Solution :Data SUPPLIED `N=1,a=0.18xx10^(-3)m, lamda=600xx10^(-9)m` `a sin theta =nlamda` Since `theta` is a very SMALL `sin theta ~~ theta` `:. theta=(n lamda)/a=(1xx600xx10^(-9))/(0.18xx10^(-3))=3.33xx10^(-3)`radian `:.`Total angular width `=2 theta=6.66xx10^(-3)` radian |
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