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Please answer my questionWrite a phthagorean triplet whose one side is 68th class

Answer»

GIVEN :-

TO FIND :-

  • The Pythagorean triplet.

SOLUTION :-

☞ Formula = [ 2m, m²-1, m²+1 ]

Here, 2M = 6

=> m = 6/2

=> m = 3

Then, m² - 1 = (3)² - 1

= 9 - 1

= 8

Then, m² + 1 = (3)² + 1

= 9 + 1

= 10

Hence the required Pythagorean triplet is

[ 6, 8, 10 ]

VERIFICATION :-

☞ In a Pythagorean triplet ,

a² + b² = c²

Since, • a = 6

• b = 8

• c = 10

Therefore, (6)² + (8)² = (10)²

=> 36 + 64 = 100

=> 100 = 100

L.H.S = R.H.S

HENCE VERIFIED


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