InterviewSolution
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Please anyone be mine |
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Answer» Iftan3AtanA=K(k≠1)tan3AtanA=k(k≠1) then(A) cosAcos3A=k−12cosAcos3A=k−12(B) sin3AsinA=2kk−1sin3AsinA=2kk−1(C) k<13K<13(D) k>3 |
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