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Please anyone help me with this. Answer is 5 and 20 cm. Please help me with the solution ​

Answer» 5 and 20 cmStep-by-step EXPLANATION:Let x = side of ONE squareLet y = side of the other squarethen4x + 4y = 100simplify, divide by 4x + y = 25y = (25-x), use this for substitutionandx^2 + y^2 = 425Substitute (25-x) for yx^2 + (25-x)^2 = 425 (25-x)(25-x)x^2 + 625 - 50x + x^2 = 425Arrange as a QUADRATIC equationx^2 + x^2 - 50x + 625 - 425 = 02x^2 - 50x + 200 = 0(x-20)(2x-10) = 0Two solutionsx = 20 is the side of one squareor2x = 10x = 5 is the side of one squareFind y25 - 20 = 5 is the side of the other squareor25 - 5 = 20 is the side of the other squareanyway, one square side is 20, the other square side is 5See if this is true4(20) + 4(5) =80 + 20 = 100and20^2 + 5^2 = 425 hope it's helped you please follow and mark as brain list


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