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Please explain the answer questions no 1 question no 2 explain in photo of ans please explain |
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Answer» stion 1Given:Chord length = 16 cmSo, AP = PB = 16/2 = 8 cmOP = 9 cmTo FIND:Length of radius = ?Solution:(refer attachment)In ΔOAPBy Pythagoras theorem, OA² = OP² + PA²⇒ OA² = 9² + 8²⇒ OA² = 145⇒ OA = √145⇒ OA = 12.04 cm∴ The length of radius = 12.04 cmFor Question 2:Given:Radius = 10 cmLength of the chord = 12 cmTo find:CD = Distance of chord from center = ?Solution:LET us consider a POINT 'D' in the middle of the chord where the line from the center meets the chord.Now ΔCDA forms a right-angled Triangle.Here, AD = DB = 12÷2 = 6 cmAgain by Pythagoras Theorem, AC² = AD² + CD²⇒ (10)² = (6)² + CD²⇒ 100 = 36 + CD²⇒ CD² = 100 - 36⇒ CD² = 64⇒ CD = √64⇒ CD = 8 cm∴ Distance of the chord from center = 6 cm |
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