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Please factorise: 8/27x^3 +2/3x^2y+1/2xy^2+1/8y^3 |
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Answer» i am not sure but hereStep-by-step explanation:Given: The term 8/27x^3 - 1/8y^3 To find: FACTORISE the given term. SOLUTION: Now we have given the term 8/27x^3-1/8y^3 We can rewrite it as: 8/27x^3-1/8y^3 = (2x/3)^3 - (y/2)^3 Now we know the FORMULA: (a^3 - B^3) = (a - b)(a^2 + ab + b^2) So applying this for given term, we get: (2x/3)^3 - (y/2)^3 = (2x/3 - y/2) x ((2x/3)^2 + (2x/3)(y/2) + (y/2)^2) = (2x/3 - y/2) x (4x^2/9 + xy/3 + y^2/4) |
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