Answer:

Step-by-step explanation:

Given JOHN and jivanti together have 45 MARBLES

LET the number of Marbles John had be= x

Then the number of marbles jivanti had= 45-x

Both of them lost 5 Marbles each

Therefore, the number of marbles John had= x-5

The number of marbles jivanti had= 45-x-5= 40-x

Now product of the number of Marbles =124

Therefore , (x-5)(40-x)=124

40- x²-200+5x=124

-x²+45x-200-124=0

x² -45x+324=0. (Multiplying by(-1))

By factorisation method

x²-36x-9x+324=0

x(x-36) - 9(x-36)=0

(x-36)(x-9)=0

x=36 or x= 9

When John has 36 Marbles and jivanti has = 45-x= 45-36=9 marbles

When John has 9 Marbles and jivanti has= 45-x= 45- 9= 36 marbles

ii) Let the number of toys produced on that day be x.

Therefore the COST of production of each toy that day= 55 - x

So the total cost production that day=number of toys× cost of production of each toy that day

Total cost of production of toy=

x × (55-x)

A.T.Q..

x(55-x)=750

55x -x²= 750

-x²+55x-750=0

x²-55x+750=0

x²- 30x -25x+750=0

x(x-30)-25(x-30)=0

(x-30)(x-25)=0

x-30=0

x=30

x-25=0

x=25

Hence, the number of toys produced= x=25 or 30