x+1=0

x=−1

8×1+4+5=17

Sometimes referred to as the INCOMPRESSIBILITY, the bulk modulus is a measure of the ability of a substance to withstand changes in VOLUME when under compression on all sides. ... It is equal to the quotient of the applied PRESSURE divided by the relative deformation.Given:

A WOODEN block of mass 400 gram float vertically in a liquid of density 0.8 gram/cm cube. The volume of the block is 625 cm³.

To find:

Volume of block above liquid surface ?

Calculation:

In case of floating, the weight of the block is being balanced by the buoyant force:

\therefore \: F_{b} = mg∴F

b

=mg

\implies \: (V_{inside}) \rho g = (V_{total}) \sigma g⟹(V

inside

)ρg=(V

total

)σg

\implies \: \dfrac{V_{inside}}{V_{total}} = \dfrac{ \sigma}{ \rho}⟹

V

total

V

inside

=

ρ

σ

\implies \: \dfrac{V_{inside}}{625} = \dfrac{ (\FRAC{400}{625} )}{ 0.8}⟹

625

V

inside

=

0.8

(

625

400

)

\implies \: \dfrac{V_{inside}}{625} = \dfrac{ 0.64}{ 0.8}⟹

625

V

inside

=

0.8

0.64

\implies \: \dfrac{V_{inside}}{625} = 0.8⟹

625

V

inside

=0.8

\implies \: V_{inside} = 500 \: {cm}^{3}⟹V

inside

=500cm

3

\implies \: V_{outside} =(625 - 500 )\: {cm}^{3}⟹V

outside

=(625−500)cm

3

\implies \: V_{outside} =125 \: {cm}^{3}⟹V

outside

=125cm

3