1.

Please help me solve the question ​

Answer»

Step-by-step explanation:

in the triangle x=2x+3

in the square x=3x/2+7

in the CIRCLE x=x-3

a) 2*∆6+[]3-O1

= 2(2*6+3)+(3*3/2+7)-(1-3)

= (2*15)+(9/2+7)-(-2)

= 30+23/2+2

= 32+23/2

= 87/2

b) 1/2*[]2+O8-3*∆0

= 1/2(3*2/2+7)+(8-3)-3(2*0+3)

= 1/2(3+7)+5-3(0+3)

= 1/2*10+5-9

= 5+5-9

= 1


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