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Answer»

I have done a lot of hard work for giving you this answer.Please mark me brainliest.Step-by-step EXPLANATION:to prove: ∠adc= ∠ acdgiven: ∠1= ∠2, ∠b= ∠3in triangle ebc ,∠6+ ∠b+ ∠1+ ∠2=180° {angle sum property}REPLACING ∠ B with ∠ 3∠6+ ∠1+ ∠2+ ∠3=180°since ∠,1= ∠2 hence ∠ 2+ ∠1 can be written as 2∠1∠6+2 ∠1+ ∠3=180°------------{1}now in triangle edc ,∠4+ ∠6+ ∠1=180°{angle sum property}∠6=180-{ ∠1+ ∠4}------------{2}from{2}180-{ ∠1+ ∠4}+2 ∠1+ ∠3=180°2 ∠1+ ∠3= ∠1+ ∠4 + 180-1802 ∠1- ∠1+ ∠3= ∠4∠1+ ∠3= ∠4hence proved , ∠ adc= ∠acd



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