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Please help ! Trigonometry question.

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Answer:

HI here's your answer

Step-by-step explanation:

\frac{1+tan^{2}A }{1+cot^{2} A}

as tan^{2} A = \frac{sin^{2}A }{cos^{2}A }

and cot^{2} A = \frac{cos^{2}A }{sin^{2}A }

LET substitute the values in the initial equation we GET,

\frac{1+\frac{sin^{2}A }{cos^{2}A } }{1+\frac{cos^{2} A}{sin^{2} A} }

by solving the above we get,

\frac{\frac{cos^{2}A+sin^{2}A }{cos^{2} A} }{\frac{sin^{2}A+cos^{2} A }{sin^{2} A} }

as sin^{2}A+cos^{2} A=1

substituting the value in the above equation we get,

\frac{\frac{1}{cos^{2}A } }{\frac{1}{sin^{2} A} }

which can be simplified as ,

\frac{sin^{2} A}{cos^{2} A}

which is,

tan^{2}A

Mark as BRAINLIEST if you are SATISFIED with my answer


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