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???please need an answer??? |
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Answer» First compute for the indefinite integral ∫ 4x - 5 DX = ∫4x dx - ∫5dx = 4∫x dx - 5X = 4 (x^2)/2 - 5x = 2x^2 - 5x + C now, (0->2) ∫ | 4x - 5 dx | = ( 2x^2 - 5x ) | (x=2) - (2x^2 - 5x) | (x=0) = (8-10) - (0) = (-2) (ANS.) |
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