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Please solve quickly ????? |
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Answer» n:- 4P + 3q = 14 .......(i)eq3p - 4Q = 23 ........(ii) eqSubstitute the (i)st equation, we get 4p + 3q = 14 4p = 14 - 3q Now put the value of p on (ii) eq we get TAKE a lcm USE cross multiplication, we get Now put the value of q on i st equation 4p + 3q = 144p + 3 × ( - 2) = 144p - 6 = 144p = 20P = 5 Answer:- p= 5 and q = - 2 |
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