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Please solve this question with explanations. |
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Answer» A CIRCLE with radius = 1 cm . QR = 1 ∠QRP = 2°To FIND : ∠RQS Solution:in Δ PQRPQ = QR = 1 => ∠QPR = ∠QRP = 2°=> ∠RQP = 180° - 2° - 2° = 176°in Δ QPSPQ = PS = 1 ( Radius)=> ∠PQS = ∠PSQ∠PQS + ∠PSQ + ∠QPS = 180°∠QPS = ∠QPR = 2°=> 2∠PQS + 2° = 180°=> ∠PQS = 89°∠RQP = ∠RQS + ∠PQS=> 176° = ∠RQS + 89°=> ∠RQS = 87°∠RQS = 87° Learn More:Find the radius of a circle in which a central ANGLE of 45degree ... brainly.in/question/6190885 |
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