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Please tell fast ❤️~Question no •8 |
Answer» Given :-● Consider a triangle ABC . WHOSE opposite angles are EQUAL. To Prove :-● AB = AC Construction:-Draw a bisector of angle A such that it INTERSECTING BC at D Proof :-Now, In ΔABC In ΔBAD and ΔCAD Angle B = Angle C. ( Given) Angle BAD = Angle CAD [By construction , D is the bisector of ΔA) AD = AD ( Common) By AAS congruence, ΔBAD and ΔCAD are congruent. By CPCT AB = AC Hence, The side opposite to equal angles are equal in a triangle. |
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