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Please tell fast ❤️~Question no •8​

Answer»

Given :-

● Consider a triangle ABC . WHOSE opposite angles are EQUAL.

To Prove :-

● AB = AC

Construction:-

Draw a bisector of angle A such that it INTERSECTING BC at D

Proof :-

Now, In ΔABC

In ΔBAD and ΔCAD

Angle B = Angle C. ( Given)

Angle BAD = Angle CAD

[By construction , D is the bisector of ΔA)

AD = AD ( Common)

By AAS congruence, ΔBAD and ΔCAD are congruent.

By CPCT

AB = AC

Hence, The side opposite to equal angles are equal in a triangle.



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