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Plot of "log" x/m against log p is a straight line inclined at an angle of 45^@. When the pressure is 0.5atm and k value is 10, the amount of solute adsorbed per gram of adsorbent will be |
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Answer» Solution :`"log" x/m = log K + 1/n "log P"` `tan 45^@ , 1/n = 1 , x/m = K.P.^(1/n) , 10 XX 0.5= 5 
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