| 1. |
Plot the points A(7,0), B(2,5), C(7,5), D(5,3), E(2,3), F(2,-2), G(4,-4), H(-4,-4), I (-2,-2), J(-2,3), K(-5,3), L(-7,5), M(-2,5). Join them in order(A to B to C and so on) Find the areas of the triangle ABM, Trapeziums (BCDE, FGHI, JKLM), and rectangle MBFI. Hence find the total area of the figure so formed |
|
Answer» Given : points A(0,7), B(2,5), C(7,5), D(5,3), E(2,3), F(2,-2), G(4,-4), H(-4,-4), I (-2,-2), J(-2,3), K(-5,3), L(-7,5), M(-2,5). To find : areas of the triangle ABM, Trapeziums (BCDE, FGHI, JKLM), and rectangle MBFI. Solution: triangle ABM, BM is the base = 4 (= 2 -(-2)) Height = 2 = ( 7 - 5) Area = (1/2)*4*2 = 4 sq units Area of Trapeziums BCDE , BC = 5 DE = 3 , BE ( height) = 2 Area = (1/2)(5 + 3) * 2 = 8 sq units Area of Trapeziums FGHI , FI = 4 GH = 8 , ( height) = 2 Area = (1/2)(4 + 8) * 2 = 12 sq units Area of Trapeziums JKLM , JK = 3 LM = 5 , JM ( height) = 2 Area = (1/2)(5 + 3) * 2 = 8 sq units rectangle MBFI. MB = 4 BF = 7 Area = 4 * 7 = 28 sq units Total area = 4 + 8 + 12 + 8 + 28 = 60 sq units Learn more: Find the area of the given figure withTU = 6 cm, SR = 8 cm, UR = 15 ... In the adjoining figure ABCD is a trapezium into which parallel sides ... |
|