Plotting a graph of log t_(1//2) against log [A]_(0) of a rectant for a first order reaction, the slope will

Plotting a graph of log t_(1//2) against log [A]_(0) of a rectant for

1.	Plotting a graph of log t_(1//2) against log [A]_(0) of a rectant for a first order reaction, the slope will
Answer» `-1` `-2` 0 `+1` SOLUTION :`t_(1//2)=0.693/K` `logt_(1//2)=log0.693-log K=`consatnt

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Plotting a graph of log t_(1//2) against log [A]_(0) of a rectant for a first order reaction, the slope will

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