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Pls help me with this qs with proper explaination wrong answers would be reported |
| Answer» HOLA MATE First speed of ram - 2 km/hlet be the distance between school and ram's HOUSE - XAnd LET 't' be the time to reach schoolNow D = v/tX = 2/tt = 2/X = X/2In first case ram REACHED 6 min LATE t = T + 6/60t = T + 1/10then X/2 = T + 1/10 .....( i )Now In second case ram reached 10 min earlierthent = T - 10/60t = T - 1/6thenX/3 = T - 1/6 ......( ii )Now ( i ) - ( ii ) we get X/6 = 1/10 + 1/6X/6 = 8/30X = 1.6 km | |