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PLS HELP!!! URGENT. I NEED THE ANSWER AND AM NOT GETTING IT. |
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Answer» (√3) tan θ = 3 sin θ To find :VALUE ofsin²θ - cos²θ Identity used :tan x = sin x ÷ COS xsin²x + cos²x = 1Solution :(√3) tan θ = 3 sin θ Squaring both side _______________________________________________Now , we know that ,sin²θ + cos²θ = 1sin²θ = 1 - cos²θ On PUTTING value of cos²θ from EQUATION 1 into above equation, we get;_______________________________________________Now put value of sin²θ & cos²θ in sin²θ - cos²θ ._______________________________________________ANSWER : (1/3) |
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