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∠a=105°, ∠b= 35°, ∠c=40°Step-by-step explanation:Given:∠DAC=35°  ∠CBX= 75°(EXTERIOR ANGLE)To find:∠a, ∠b, ∠c.SOLVE:If CD║AB and AC is the transversal then,=>∠DAC=∠b= 35°                      (Alternate INTERIOR ANGLES are EQUAL)If AD║BC and AB is the  transversal then,=>∠DAB=∠CBX=75°                  (Corresponding angles are equal)But ∠DAB= ∠DAC+∠cSo,∠DAC+∠c= 75°=> 35°+∠c= 75°           =>∠c= 75-35= 40°∠CBA + ∠CBX= 180°                                                (LINEAR Pair)=> ∠CBA + 75°= 180°=>∠CBA = 180° - 75°= 105°So, ∠CBA= ∠a=105°               (Opposite angles in Parallelogram are equal)HOPE THE ANSWER HELPED!!



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