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Pls solve it...pls i need the ans....pls.... |
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Answer» Answer: AD=60cm, BC=24cm, RADIUS of SMALLER circle=20 cm Step-by-step explanation: GIVEN OA=34cm OP=16cm Using pythagoras theorem OA square=OP square+AP square 34 square=16 square+ AP square AP square=34 square-16 square AP square=900 AP=30 cm AD=2AP=2×30 =60 cm BP=AP-AB=30-18=12cm BC=2BP=2×12=24 cm BP=12cm, OP=16cm OB is the HYPOTENUSE of triangle OBP and also radius of the small circle. By pythagoras theorem OB square=OP square+BP square OB square=16 square+12 square OB square=400 OB=20 cm |
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