1.

Pluto has 1//500 the mass and 1//15 the radius of Earth. What is the value of g on the surface of Pluto ?

Answer»

`0.3 m//s^(2)`
`1.6 m//s^(2)`
`2.4 m//s^(2)`
`4.5 m//s^(2)`

Solution :The gravitiational ACCELERATION at the surface of a PLANET of mass M and radius R is given by the EQUATION `g=GM//R^(2)` . Therefore
`g_("Pluto")=G(M_("Pluto"))/(R_("Pluto")^(2))=G((1)/(500)M_("Earth"))/(((1)/(15)R_("Earth"))^(2))=(15^(2))/(500)* G(M_("Earth"))/(R_("Earth")^(2))=(225)/(500)(10 m//s^(2))=4.5 m//s^(2)`


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