1.

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Answer:

Length of diagonal of cuboid =

l

2

+B

2

+c

2

SURFACE AREA of cuboid =2(lb+bh+hl)

Assume -

⇒length=l

Breadth=b

Depth=h

Given eq (1) l+b+h=19

eq (2) length of diagonal =11

⇒

l

2

+b

2

+h

2

=11

Simplifying eq (2)

⇒l

2

+b

2

+h

2

=121

Taking (l+b+h)

2

=l

2

+b

2

+h

2

+2lb+2bh+2lh

substituting values

⇒(19)

2

=121+2(lb+bh+lh)

⇒361−121=2(lb+bh+lh)

⇒240=2(lb+bh+lh)

∴ Surface area of cuboid =240.

Step-by-step explanation:

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