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PLZ HELP!!! GEOMETRY ASAP |
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Answer» Answer: First join AO and BQ. ( I am SORRY I am not able to put a picture but you will surely understand continue reading ) We know that, tangents are perpendicular to the radii of the circle. Hence AO and BQ are perpendicular to AC. Now in triangles AOC and BQC, angle OAC = angle BQC = 90 DEGREES. and angle ACO = angle BCQ By AA similarity, triangles ACO and BCQ are similar. So according to the properties of similar triangles, AO / QB = CO / CQ. Hence proved. Please mark me as the Brainliest. I did my level best to make it easily understandable. please ignore if any grammatical mistakes are PRESENT. |
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