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plz help me to factorise this polynomial.I will follow u mark as brainliest |
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Answer» Step-by-step explanation: a2" was replaced by "a^2". 1 more similar replacement(s). (((5 • (a3)) + 11a2) + 4a) - 2 ((5a3 + 11a2) + 4a) - 2 5a3+11a2+4a-2 is not a perfect cube The FACTOR Theorem states that if P/Q is root of a polynomial then this polynomial can be DIVIDED by q*x-p Note that q and p originate from P/Q reduced to its lowest terms In our case this means that 5a3+11a2+4a-2 can be divided with a+1 Polynomial Long Division Dividing : 5a3+11a2+4a-2 ("DIVIDEND") By : a+1 ("Divisor") dividend 5a3 + 11a2 + 4a - 2 - divisor * 5a2 5a3 + 5a2 remainder 6a2 + 4a - 2 - divisor * 6a1 6a2 + 6a remainder - 2a - 2 - divisor * -2a0 - 2a - 2 remainder 0 Quotient : 5a2+6a-2 Remainder: 0 (5a2 + 6a - 2) • (a + 1) is ur answer |
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