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Plz solve this questionasap |
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Answer» sin θ 1 − cos θ + tan θ 1 + cos θ
= sin θ ( 1 + cos θ ) ( 1 − cos θ ) ( 1 + cos θ ) + tan θ ( 1 − cos θ ) ( 1 + cos θ ) ( 1 − cos θ ) = sin θ ( 1 + cos θ ) 1 − cos 2 θ + tan θ ( 1 − cos θ ) 1 − cos 2 θ
= sin θ ( 1 + cos θ ) sin 2 θ + sin θ ( 1 − cos θ ) cos θ sin 2 θ
= 1 + cos θ sin θ + 1 − cos θ cos θ sin θ
= 1 sin θ + cos θ sin θ + 1 cos θ sin θ − 1 sin θ
= csc θ + cot θ + sec θ csc θ − csc θ
= sec θ csc θ + cot θ |
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