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Answer» Answer: Theorem: The diagonals of a parallelogram bisect each other. PROOF: Given ABCD, LET the diagonals AC and BD intersect at E, we must prove that AE ∼ = CE and BE ∼ = DE. The converse is also true: If the diagonals of a QUADRILATERAL bisect each other, then the quadrilateral is a parallelogram. |
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