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SINCE, you haven't attached any image, we shall look at every possibility in BRIEF.

Gene under consideration is a X linked recessive allele, the conditions in which it can express itself :

In a pair of homozygous recessive alleles. (Incase of woman)

In a GENOTYPE of the type : XY (Men)

Usually when females inherit a gene for sex linked recessive disorder, the latter is unable to express itself due to the PRESENCE of a pure X gene (DOMINANT). They often end up as carriers.

Case 1 : Inherited from a carrier mother.

Let us assume she married an afflicted man. (X^c will be X chromosome)

\begin{array}{|c|c|c|}\cline{1-3} & \sf X^c & \sf Y \\ \cline{1-3}\sf X^c & \sf X^cX^c & \sf X^cY \\ \cline{1-3}\sf X & \sf XX^c & \sf XY \\ \cline{1-3} \end{array}

A carrier female

Affected male and female

Normal male

In the case, 3 off springs inherit the gene but only one isn't affected.

Let us assume she married a normal man. (X chromosome)

\begin{array}{|c|c|c|}\cline{1-3} & \sf X & \sf Y \\ \cline{1-3}\sf X^c & \sf XX^c & \sf X^cY \\ \cline{1-3}\sf X & \sf XX & \sf XY \\ \cline{1-3} \end{array}

A normal male and female

A carrier female

An affected male

Again, two off springs inherit the gene but only one isn't affected.

\rule{300}{2}

Case 2 : Inherited from an affected mother.

Let us assume she married an affected man.

\begin{array}{|c|c|c|}\cline{1-3} & \sf X^c & \sf Y \\ \cline{1-3}\sf X^c & \sf X^cX^c & \sf X^cY \\ \cline{1-3}\sf X^c & \sf X^cX^c & \sf X^cY \\ \cline{1-3} \end{array}

All the off springs are affected.

Let us assume she married a normal man.

\begin{array}{|c|c|c|}\cline{1-3} & \sf X & \sf Y \\ \cline{1-3}\sf X^c & \sf XX^c & \sf X^cY \\ \cline{1-3}\sf X^c & \sf X^cX^c & \sf X^cY \\ \cline{1-3} \end{array}

Two affected males and one affected female.

One carrier female

In the case, 4 off springs inherit the gene but only one isn't affected.

\rule{300}{2}

\rule{300}{2}


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