1.

Point A on the rod AB has an acceleration of 5m//s^(2) and a velocity of 6m//s at an instant as shown in the figure. The acceleration of the end B at the same moment is:

Answer»

`-80/3hati m//s^(2)`
`80/3hatim//s^(2)`
`-40/3hatim//s^(2)`
`-75/6hatim//s^(2)`

SOLUTION :`veca_(B)=veca_(A)+(VEC(alpha)xxvec(r_(B,A)))-omega^(2)vec(r_(B,A))`
`=-5j+4alphai+3alphaj-(12i-16j)`
`a_(B)` along `y` axis should be ZERO
`implies 11+3alpha=0`
`impliesalpha=-4/3"RAD"//s^(2)`
`a_(B)=(4alpha-12)i=-80/3im//s^(2)`


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