1.

Polarisation of electrons in acrolein may be written as

Answer»

`OVERSET(-delta)(CH_(2))=CH-CH=O`
`overset(-delta)(CH_(2))=CH-CH=overset(+delta)(O)`
`overset(-delta)(CH_(2))=overset(+delta)(CH)-CH=O`
`overset(+delta)(CH_(2)) = CH - CH = overset(-delta)(O)`

Solution :Oxygen is highly ELECTRONEGATIVE than carbon, so it acquires partiallynegative charge and carbon ATOM acquire partially positive charge which is transferred to the last carbon atom.


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