1.

Position of particle is given by S = t^3 – 2t^2 + 5t + 4 (a) Find the position of particle at t = 1 sec (b) Find the first derivative of S at t = 1 sec (c) Find the second derivative of S t = 1 sec

Answer»


Answer :a = 8,b = 4,c = 2, b, `cos theta=(vecF_(1),vecF_(2))/(|vecF_(1)||vecF_(2)|)RARR theta=cos^(-1)((3)/(5sqrt2))` c, `F_(1)cos theta=(vecF_(1),vecF_(2))/(|vecF_(2)|)=(6)/(5)`


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