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Potassium has a bcc structure with nearest neighbor distance 4.52Å. Its atomic weight is 39. its density will be ……………… .

Answer»

`"915 kg m"^(-3)`
`"2142 kg m"^(-3)`
`"452 kg m"^(-3)`
`"390 kg m"^(-3)`

Solution :`(rho)=(nM)/(a^(3)N_(A))" For bcc n = 2 M = 39."` NEAREST distance `2r=4.52`
`a=(4r)/(SQRT3)=(2xx4.52xx10^(-10))/(sqrt3)=5.21xx10^(-10)`
`rho=(2xx39)/((5.21xx10^(-10))^(3)XX(6.023xx10^(23)))""rho="915 kg m"^(-3)N_(A)`


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