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Potential drop in a dielectric is equal to _______(a) Electric field strength*thickness(b) Electric field strength*area of a cross section(c) Electric field strength(d) ZeroThe question was posed to me in an internship interview.I'd like to ask this question from Composite Dielectric Capacitor topic in section Capacitance and Capacitors of Basic Electrical Engineering

Answer»

Correct choice is (a) ELECTRIC field strength*thickness

The BEST explanation: When a DIELECTRIC is introduced between the two plates of a parallel plate capacitor, the potential DIFFERENCE decreases by the VALUE of the product of electric field strength*thickness which is the potential difference of the dielectric.



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