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Power applied to a particle varices with time as `P =(3t^(2)-2t + 1)` watt, where t is in second. Find the change in its kinetic energy between time `t=2s` and `t = 4 s` .A. 32 JB. 46 JC. 61 JD. 102 J |
Answer» Correct Answer - B (b) Change in kinetic energy of the particle `DeltaKE=W=int_(2)^(4)Pdt=int_(2)^(4)(3t^(2)-2t+1)dt=[t^(3)-t^(2)+]_(2)^(4)=46J` |
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