Power dissipated in an `L-C-R` series circuit connected to an `AC` source of emf `epsilon` isA. `(E^(2)R)/[[R^(2) + (Lomega - (1)/(Comega))^(2)]`B. `(E^(2) sqrt(R^(2) + (Lomega - (1)/(Comega))^(2)))/R`C. `(E^(2) [R^(2) + (Lomega - (1)/(Comega))^(2)])/R `D. `(E^(2)R)/(sqrt(R^(2) + (Lomega (1)/(Comega))^(2))`

Power dissipated in an `L-C-R` series circuit connected to an `AC` sou

1.	Power dissipated in an `L-C-R` series circuit connected to an `AC` source of emf `epsilon` isA. `(E^(2)R)/[[R^(2) + (Lomega - (1)/(Comega))^(2)]`B. `(E^(2) sqrt(R^(2) + (Lomega - (1)/(Comega))^(2)))/R`C. `(E^(2) [R^(2) + (Lomega - (1)/(Comega))^(2)])/R `D. `(E^(2)R)/(sqrt(R^(2) + (Lomega (1)/(Comega))^(2))`
Answer» Correct Answer - A `P = V_(rms) I_(rms) cos phi = V_(rms) V_(rms)/(Z) R /(Z)` `(V_(rms)^(2)R)/(Z^(2)) = (E^(2)R)/(R^(2) + (Lomega- (1)/(Comega))^(2))` .

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