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Power dissipated in an `L-C-R` series circuit connected to an `AC` source of emf `epsilon` isA. `epsi^(2)R//sqrt(R^(2)+(Lomega-(1)/(Comega))^2)`B. `epsi^(2)R//[R^(2)+(Lomega-(1)/(Comega))^2]`C. `epsi^(2)R//sqrt([R^(2)+(Lomega-(1)/(Comega))^2])//R`D. `(epsi^(2)[R^(2)+(Lomega-(1)/(Comega))^2])/(R)` |
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Answer» Correct Answer - B `P_(av)=E_(rms). I_(rms) cos phi` ` epsi . (epsi)/(z) . (R)/(z)= (epsi^(2)R)/(z^(2))` `=( epsi^(2)R)/(R^(2)+(omegaL-(1)/(omegaC))^(2))` |
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