1.

Power radiated by half-wave dipole with maximum current amplitude 10A is ______(a) 3.65kΩ(b) 3.650Ω(c) 0.365kΩ(d) 36.50ΩI got this question by my school principal while I was bunking the class.My question comes from Radiation Resistance topic in chapter Antenna Parameters of Antennas

Answer»

The correct ANSWER is (a) 3.65kΩ

To elaborate: For a half-wave dipole the radiation RESISTANCE is 73Ω.

 \(I_{rms}=\FRAC{I_m}{\sqrt{2}}=\frac{10}{\sqrt{2}}=5\sqrt{2}\)

POWER radiated Prad=Irms^2 Rrad=(5√2)^2×73=3650Ω=3.65kΩ



Discussion

No Comment Found

Related InterviewSolutions