1.

Power supplied to a mass `2 kg` varies with time as `P = (3t^(2))/(2)` watt. Here `t` is in second . If velocity of particle at `t = 0 is v = 0`, the velocity of particle at time `t = 2s` will be:A. 1 m/sB. 4m/sC. 2m/sD. `sqrt(2) m//s`

Answer» Correct Answer - C
Applying work energy theorem
`K_(f)=K_(i)`+work done
`1/2 mv^(2)=0+int_(0)^(2) Pdt=int_(0)^(2)(3t^(2))/2 dt`
Solving we get v=2m/s.


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